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w^2+17w+12=0
a = 1; b = 17; c = +12;
Δ = b2-4ac
Δ = 172-4·1·12
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{241}}{2*1}=\frac{-17-\sqrt{241}}{2} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{241}}{2*1}=\frac{-17+\sqrt{241}}{2} $
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